jayelblock
·I'm off a little, I think, but something along these lines?
Right
Solution
Two Russels/to Russell's
Para docks/Paradox
If R contains itself, then R must be a set that is not a member of itself by the definition of R, which is contradictory.
Right
Solution
Two Russels/to Russell's
Para docks/Paradox
If R contains itself, then R must be a set that is not a member of itself by the definition of R, which is contradictory.