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davebin
·
在欧米茄9300机芯中，表盘上的计时分针和计时时针是同轴的。然而，在计时传动轮系结构中，计时分轮和计时时轮却是纵向平行排列的，其旁边还有一个变速齿轮。它们之间是怎样的传动关系呢？
我想知道欧米茄9300机芯中的减速齿轮是如何将动力传输到计时小时轮的？它会经过中间的计时分钟轮吗？
Discussion on the Structure of the Chronograph Transmission Bridge in Omega 9300 Movement
在欧米茄9300机芯中，表盘上的计时分针和计时时针是同轴的。然而，在计时传动轮系结构中，计时分轮和计时时轮却是纵向平行排列的，其旁边还有一个变速齿轮。它们之间是怎样的传动关系呢？
我想知道欧米茄9300机芯中的减速齿轮是如何将动力传输到计时小时轮的？它会经过中间的计时分钟轮吗？
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Trev
··The Architect我们不会说中文😀
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Deafboy
··His Holiness Puer SurdusYour Chinese text translates as follows (by perplexity):
In the Omega 9300 movement, the chronograph minute hand and chronograph hour hand on the dial are coaxial. However, in the chronograph gear transmission system, the chronograph minute wheel and the chronograph hour wheel are arranged longitudinally and parallel to each other, with a reduction gear located beside them. What is the transmission relationship between them?
I would like to know how the reduction gear in the Omega 9300 movement transmits power to the chronograph hour wheel. Does it pass through the intermediate chronograph minute wheel?
Perplexity has an answer too.
In the Omega Caliber 9300, the gear train for the chronograph uses a column wheel and vertical clutch system, differing from older lateral-clutch designs. The chronograph minute and hour hands are coaxial on the dial, but inside the movement the minute-recording wheel and hour-recording wheel are mounted on parallel axes connected through an intermediate reduction gear. When the chronograph is engaged, torque is transferred from the vertical clutch driving wheel to the minute counting wheel; the reduction gear then steps down this rotation to drive the hour counting wheel at one twelfth of the speed. Thus, the hour wheel’s motion is mechanically linked through the intermediate gearing—effectively “through” the minute-register system, but with its own reduction ratio determining the 12:1 hour/minute correspondence within the chronograph mechanism.
In the Omega 9300 movement, the chronograph minute hand and chronograph hour hand on the dial are coaxial. However, in the chronograph gear transmission system, the chronograph minute wheel and the chronograph hour wheel are arranged longitudinally and parallel to each other, with a reduction gear located beside them. What is the transmission relationship between them?
I would like to know how the reduction gear in the Omega 9300 movement transmits power to the chronograph hour wheel. Does it pass through the intermediate chronograph minute wheel?
Perplexity has an answer too.
In the Omega Caliber 9300, the gear train for the chronograph uses a column wheel and vertical clutch system, differing from older lateral-clutch designs. The chronograph minute and hour hands are coaxial on the dial, but inside the movement the minute-recording wheel and hour-recording wheel are mounted on parallel axes connected through an intermediate reduction gear. When the chronograph is engaged, torque is transferred from the vertical clutch driving wheel to the minute counting wheel; the reduction gear then steps down this rotation to drive the hour counting wheel at one twelfth of the speed. Thus, the hour wheel’s motion is mechanically linked through the intermediate gearing—effectively “through” the minute-register system, but with its own reduction ratio determining the 12:1 hour/minute correspondence within the chronograph mechanism.
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davebin
·Your Chinese text translates as follows (by perplexity):
In the Omega 9300 movement, the chronograph minute hand and chronograph hour hand on the dial are coaxial. However, in the chronograph gear transmission system, the chronograph minute wheel and the chronograph hour wheel are arranged longitudinally and parallel to each other, with a reduction gear located beside them. What is the transmission relationship between them?
I would like to know how the reduction gear in the Omega 9300 movement transmits power to the chronograph hour wheel. Does it pass through the intermediate chronograph minute wheel?
Perplexity has an answer too.
In the Omega Caliber 9300, the gear train for the chronograph uses a column wheel and vertical clutch system, differing from older lateral-clutch designs. The chronograph minute and hour hands are coaxial on the dial, but inside the movement the minute-recording wheel and hour-recording wheel are mounted on parallel axes connected through an intermediate reduction gear. When the chronograph is engaged, torque is transferred from the vertical clutch driving wheel to the minute counting wheel; the reduction gear then steps down this rotation to drive the hour counting wheel at one twelfth of the speed. Thus, the hour wheel’s motion is mechanically linked through the intermediate gearing—effectively “through” the minute-register system, but with its own reduction ratio determining the 12:1 hour/minute correspondence within the chronograph mechanism.
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- 1
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davebin
·Your Chinese text translates as follows (by perplexity):
In the Omega 9300 movement, the chronograph minute hand and chronograph hour hand on the dial are coaxial. However, in the chronograph gear transmission system, the chronograph minute wheel and the chronograph hour wheel are arranged longitudinally and parallel to each other, with a reduction gear located beside them. What is the transmission relationship between them?
I would like to know how the reduction gear in the Omega 9300 movement transmits power to the chronograph hour wheel. Does it pass through the intermediate chronograph minute wheel?
Perplexity has an answer too.
In the Omega Caliber 9300, the gear train for the chronograph uses a column wheel and vertical clutch system, differing from older lateral-clutch designs. The chronograph minute and hour hands are coaxial on the dial, but inside the movement the minute-recording wheel and hour-recording wheel are mounted on parallel axes connected through an intermediate reduction gear. When the chronograph is engaged, torque is transferred from the vertical clutch driving wheel to the minute counting wheel; the reduction gear then steps down this rotation to drive the hour counting wheel at one twelfth of the speed. Thus, the hour wheel’s motion is mechanically linked through the intermediate gearing—effectively “through” the minute-register system, but with its own reduction ratio determining the 12:1 hour/minute correspondence within the chronograph mechanism.
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Deafboy
··His Holiness Puer SurdusHello, I would also like to ask that in the 9300 movement, it adopts a double-layer third wheel structure. The upper third wheel is connected to the chronograph second wheel, the vertical clutch, and the center wheel. Then, this center wheel drives the running second wheel. Since the center wheel rotates slowly, how does it drive the running second wheel? Or does the upper third wheel in the middle play a role in speed change?
In the Omega 9300 movement, the double-layer third wheel structure consists of an upper third wheel connected to the chronograph seconds wheel, the vertical clutch, and the center wheel. The center wheel, which rotates relatively slowly, is responsible for driving the running seconds wheel.
The way this works is that the upper third wheel does indeed play a role in changing the speed. The center wheel drives the upper third wheel, which then transmits motion to the running seconds wheel at an appropriate speed. This intermediate step allows the slower rotation of the center wheel to be converted into the faster rotation needed for the running seconds wheel.
So, the upper third wheel acts as a speed-changing intermediary between the center wheel and the running seconds wheel, enabling the correct rotational speed for the running seconds to keep accurate time.